做到作业最后一题结果得出个一元6次方程, 计算器没法计, 没法, 只能编程取近似值算了.

到目前为止还未是不是自己计错数.

 

//solve the acsc problem's question for the equation:
//
//  0=-120-5(1-1/((1+i)(1+i)(1+i)(1+i)(1+i)))/i+50(1-1/((1+i)(1+i)(1+i)(1+i)))/i(1+i)
//
//Take the nearest result, so set 0.00000000000001 almost equal to 0
//

#include <iostream>
#include <cstdlib>
#include <cmath>

using namespace std;

const float min=0.00000000000001;

int main()
{
   float i,tempResult,absVal;
 
   for (i=0.1;i<0.12;i=i+0.0000001)
    {
     tempResult=-120-5*(1-pow((1+i),-5))/i+50*(1-pow((1+i),-4))/(i*(1+i));
     if (tempResult==0)
       {
         cout<<"The yield rate is: "<< i <<endl;
         return 0;
       }
     else
       {
         absVal=abs(tempResult);
         if (absVal<=min)
           cout<<"The yield rate is: "<< i <<endl;
       }
    } 
   
    return 1;
}

 

Script started on Sat Nov 19 20:56:54 2005
 
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Script on hercules[1]% acsc

The yield rate is: 0.113387
Script on hercules[2]% exit

exit

script done on Sat Nov 19 20:57:06 2005